Q47 / 150 · MHT CET 2023 (14 May Shift 1) · Chemistry

Calculate half life of first order reaction if rate constant of reaction is $2.772 \times 10^{-3} \mathrm{~s}^{-1}$

  • A
    $125 \mathrm{~s}$
  • Correct answer
    B
    $250 \mathrm{~s}$
  • C
    $100 \mathrm{~s}$
  • D
    $150 \mathrm{~s}$

Solution

$\begin{aligned} & \mathrm{k}=\frac{0.693}{\mathrm{t}_{1 / 2}} \\ \therefore \quad \mathrm{t}_{1 / 2} & =\frac{0.693}{\mathrm{k}}=\frac{0.693}{2.772 \times 10^{-3} \mathrm{~s}^{-1}}=250 \mathrm{~s}\end{aligned}$

Hence, the correct answer is option: 'B'.

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