Q17 / 170 · Manipal (MET) 2015 · Chemistry
$40 \%$ by weight solution will contain how much mass of the solute in 1 L solution, density of the solution is $1.2 \mathrm{~g} / \mathrm{mL}$ ?
- Correct answerA480 g
- B48 g
- C38 g
- D380 g
Solution
$\begin{aligned}
& \text { Molarity }=\frac{\text { solution } \times 10(\text { in litre })}{\text { molecular weight of the solute }} \\
& \text { Molarity }=\frac{40 \times 1.2 \times 10}{M \times 1000}
\end{aligned}$
Again, since $\text { Molarity }=\frac{\text { weight of the solute } / M}{\text { volume of the solution (in litre) }}$
Therefore, weight of solute $=480 \mathrm{~g}$
Again, since $\text { Molarity }=\frac{\text { weight of the solute } / M}{\text { volume of the solution (in litre) }}$
Therefore, weight of solute $=480 \mathrm{~g}$
Hence, the correct answer is option: 'A'.