Q20 / 84 · JEE Advanced 2010 (Paper 1) · Chemistry
Based on VSEPR theory, the number of 90 degree $\mathrm{F}-\mathrm{Br}-\mathrm{F}$ angles in $\mathrm{BrF}_5$ is
Correct answer: 0
Solution
In $\mathrm{BrF}_5$ number of electrons $=6$ $(1 l p+5 b p)$
So, the structure is supposed to be square pyramidal but will be distorted because of additional lp- $b p$ interaction.

Additional $\quad l p-b p$ interaction reduces the all bond angle and do not let any angle to be $90^{\circ}$. Chemical bonding Conceptual IV

Additional $\quad l p-b p$ interaction reduces the all bond angle and do not let any angle to be $90^{\circ}$. Chemical bonding Conceptual IV
Hence, the correct answer is 0.