Q20 / 84 · JEE Advanced 2010 (Paper 1) · Chemistry

Based on VSEPR theory, the number of 90 degree $\mathrm{F}-\mathrm{Br}-\mathrm{F}$ angles in $\mathrm{BrF}_5$ is

Correct answer: 0

Solution

In $\mathrm{BrF}_5$ number of electrons $=6$ $(1 l p+5 b p)$ So, the structure is supposed to be square pyramidal but will be distorted because of additional lp- $b p$ interaction. Figure
Additional $\quad l p-b p$ interaction reduces the all bond angle and do not let any angle to be $90^{\circ}$. Chemical bonding Conceptual IV

Hence, the correct answer is 0.

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