Q46 / 90 · JEE Main 2022 (29 Jul Shift 2) · Mathematics

Bag I contains 3 red, 4 black and 3 white balls and Bag II contains 2 red, 5 black and 2 white balls. One ball is transferred from Bag I to Bag II and then a ball is draw from Bag II. The ball so drawn is found to be black in colour. Then the probability, that the transferred ball is red, is

  • A
    49
  • Correct answer
    B
    518
  • C
    16
  • D
    310

Solution

Given,

In bag 1→3R, 4B & 3W

And in bag 2→2R, 5B & 2W

Let A: Drawn ball from bag II is black

And let B: Red ball transferred

Now by total probability theorem we have PA=39×510+49×610+39×510=5490

And PA∩B=39×510

So, by bayes theorem we have, PBA=PA∩BPA

=39×51039×510+49×610+39×510

=1515+24+15=1554=518

Hence, the correct answer is option: 'B'.

Relevant Questions