Q10 / 160 · AP EAMCET 2015 · Chemistry

$3.011 \times 10^{22}$ atoms of an element weighs $1.15 \mathrm{~g}$. The atomic mass of the element is

  • Correct answer
    A
    $23$
  • B
    $10$
  • C
    $16$
  • D
    $35.5$

Solution

From Avogadro's law, Avogadro's number $=$ Atomic mass of the element $\because 3.011 \times 10^{22}$ atoms of an element weigh $=1.15 \mathrm{~g}$ $\therefore 6.023 \times 10^{23}$ atoms weigh $=\frac{1.15 \times 6.023 \times 10^{23}}{3.011 \times 10^{22}}=23$

Hence, the correct answer is option: 'A'.

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