Q6 / 160 · TS EAMCET 2017 · Chemistry

Atomic radius (pm) of $\mathrm{Al}, \mathrm{Si}, \mathrm{N}$ and $\mathrm{F}$ respectively is

  • A
    $117,143,64,74$
  • Correct answer
    B
    $143,117,74,64$
  • C
    $143,47,64,74$
  • D
    $64,74,117,143$

Solution

$\mathrm{Al}, \mathrm{Si}$ belory to $3 \mathrm{rd}$ period of periodic table while $\mathrm{N}_1$ and fluorine to second period. The size of element decreases from left to right in a period hence the order of size is $\mathrm{Al}>\mathrm{Si}>\mathrm{N}>\mathrm{F}$

Hence, the correct answer is option: 'B'.

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