At time t = 0, terminal A in the circuit shown in the figure is connected to B by a key and an alternating current $\mathrm{I}\left(\mathrm{t}\right)={\mathrm{I}}_0\cos \left(\mathrm{\omega }\mathrm{t}\right)$ , with ${\mathrm{I}}_0=1\mathrm{A}$ and $\mathrm{\omega }=500\mathrm{ }$ rad/s starts flowing in it with the initial direction shown in the figure. At $\mathrm{t}=\frac{7\mathrm{\pi }}{6\mathrm{\omega }}$ , the key is switched from B to D. Now onwards only A and D are connected. A total charge Q flows from the battery to charge the capacitor fully. If $\mathrm{C}=20\mathrm{ }\mathrm{\mu }\mathrm{F},\mathrm{ }\mathrm{R}=10\mathrm{ }\mathrm{\Omega }$ and the battery is ideal with of 50V, identify the correct statement(s).

• A

  Magnitude of the maximum charge on the capacitor before $\mathrm{t}=\frac{7\mathrm{\pi }}{6\mathrm{\omega }}$ is $1\times {10}^{-3}\mathrm{ }\mathrm{C}$ .
• B

  The current in the left part of the circuit just before $\mathrm{t}=\frac{7\mathrm{\pi }}{6\mathrm{\omega }}$ is clockwise.
• Correct answer
  C

  Immediately after A is connected to D, the current in R is 10 A.
• Correct answer
  D

  $\mathrm{Q}=2\times {10}^{-3}\mathrm{ }\mathrm{C}$ .

Hence, the correct answer is options: 'C', 'D'.