At $25^{\circ} \mathrm{C}$, the percentage of ionization of $x \mathrm{M}$ acetic acid is 4.242. What is the pH of the acetic acid solution? $(\log 4.242=0.6275) ;(\log 0.04242=-1.372) \quad\left(\mathrm{K}_{\mathrm{a}}=1.8 \times 10^{-5}\right)$

• Correct answer
  A

  3.37
• B

  1.70
• C

  1.37
• D

  2.37

Hence, the correct answer is option: 'A'.