Q75 / 75 · JEE Main 2025 (23 Jan Shift 2) · Physics

At steady state the charge on the capacitor, as shown in the circuit below, is $\qquad$ $\mu \mathrm{C}$.

Correct answer: 16

Solution

$\begin{aligned} & \mathrm{i}=\left(\frac{5}{25}\right) \\ & \mathrm{Q}=\mathrm{CV} \\ & \mathrm{Q}=\left(8 \times 10^{-6}\right)\left(\frac{5}{25} \times 10\right) \\ & \mathrm{Q}=\left(\frac{8 \times 5 \times 10^{-2}}{25}\right)=16 \mu \mathrm{C}\end{aligned}$

Hence, the correct answer is 16.

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