At $27^{\circ} \mathrm{C}$ kinetic energy of 4 g of $\mathrm{H}_2$ is $x \mathrm{~J}$. What is the kinetic energy (in J ) of 6.4 g of oxygen at $127^{\circ} \mathrm{C}$ ?

• A

  $\frac{x}{15}$
• B

  $\frac{4 x}{15}$
• C

  $\frac{8 x}{15}$
• Correct answer
  D

  $\frac{2 x}{15}$

Hence, the correct answer is option: 'D'.