Q23 / 160 · AP EAMCET 2018 (22 Apr Shift 2) · Chemistry

At $T(\mathrm{~K})$ if the rate constant for a zero order reaction is $2.5 \times 10^{-3} \mathrm{~ms}^{-1}$, the time required for the initial concentration of reactant, $R$ to fall from $0.10 \mathrm{M}$ to $0.075 \mathrm{M}$ at the same temperature in seconds is

  • A
    25
  • B
    5
  • Correct answer
    C
    10
  • D
    20

Solution

$\begin{aligned} t & =\frac{\left[R_0\right]-[R]_E}{K} \quad t=\frac{0.1-0.075}{2.5 \times 10^{-3}} \\ & =\frac{0.025}{2.5 \times 10^{-3}} t=0.01 \times 10^3=10 \mathrm{~s}\end{aligned}$

Hence, the correct answer is option: 'C'.

Relevant Questions