Q8 / 160 · AP EAMCET 2023 (16 May Shift 2) · Chemistry

At $T(K)$ and pressure $P$, the diffusion rate of an ideal gas is $120 \mathrm{~mL} \mathrm{~min}^{-1}$. What is the time taken (in sec.) for $3000 \mathrm{~mL}$ of this gas for diffusion at same temperature and pressure?

  • A
    $25$
  • Correct answer
    B
    $1500$
  • C
    $250$
  • D
    $150$

Solution

Diffusion rate $=120 \mathrm{~mL}$ in one minute. $\Rightarrow$ Time required for the diffusion of $3000 \mathrm{~mL}$ will be :- $\mathrm{t}=\frac{3000}{120}=25 \text { minutes }=25 \times 60=1500 \text { seconds. }$

Hence, the correct answer is option: 'B'.

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