Q76 / 90 · JEE Main 2021 (20 Jul Shift 2) · Physics

At an angle of $30 °$ to the magnetic meridian, the apparent dip is $45 ° .$ Find the true dip:

A
$\tan^{- 1} \sqrt{3}$
B
$\tan^{- 1} \frac{1}{\sqrt{3}}$
C
$\tan^{- 1} \frac{2}{\sqrt{3}}$
Correct answer
D
$\tan^{- 1} \frac{\sqrt{3}}{2}$

Solution

$A tanδ = {tanδ}^{'} cosθ$

$= \tan 45 ° \cos 30 °$

$\tan δ = 1 \times \frac{\sqrt{3}}{2}$

$δ = \tan^{- 1} (\frac{\sqrt{3}}{2})$

Hence, the correct answer is option: 'D'.

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