At a particular locus, frequency of $A$ allele is 0.6 and that of a is 0.4 . What would be the frequency of heterozygotes in a random mating population at equilibrium?

In a stable population, for a gene with two alleles, 'A' (dominant) and 'a' (recessive), the frequency of ' $\mathrm{A}^{\prime}=\mathrm{p}$ the frequency of ' $a$ ' $=q$, According Hardy-Weinberg equation: $$ \mathrm{p}^2+2 p q+q^2=1 $$ where $\mathrm{p}^2=$ Frequency of $\mathrm{A}$ (homozygous dominant) individuals $\mathrm{q}^2=$ Frequency of aa (homozygous recessive) individuals $2 \mathrm{pq}=$ Frequency of $\mathrm{Aa}$ (heterozygous) individuals. $$ \begin{aligned} & \therefore 2 \mathrm{pq}(\text { frequency of heterozygote })= \\ & 2 \times 0.6 \times 0.4=0.48 \end{aligned} $$