At 298 K the value of -fracΔ [Br^- ]Δ t for the reaction 5 Br^- (a q)+BrO_3^-(a q)+6 H^+(a q) arrow 3 Br_2(a q)+3 H_2 O(1) is x mol L L^-1 ~min^-1 . What is the rate (in mol L^-1 ~min^-1 ) of this reaction?

Correct answer: (C) x/5. Given reaction, 5 Br^-(aq)+BrO_3^-(aq)+6 H^+(aq) arrow 3 Br_2(aq)+3 H_2 O(l) -fracΔ [Br^- ]Δ t=x ~mol ~L -1 min^-1 Rate of Reaction =-1/5 frac~d [Br^- ]dt =1/5 x

Q24 / 160 · AP EAMCET 2024 (20 May Shift 2) · Chemistry

At 298 K the value of $-\frac{\Delta\left[\mathrm{Br}^{-}\right]}{\Delta t}$ for the reaction $5 \mathrm{Br}^{-}$ $(a q)+\mathrm{BrO}_3^{-}(a q)+6 \mathrm{H}^{+}(a q) \rightarrow 3 \mathrm{Br}_2(a q)+3 \mathrm{H}_2 \mathrm{O}(1)$ is $x$ $\mathrm{mol} \mathrm{L} \mathrm{L}^{-1} \mathrm{~min}^{-1}$. What is the rate (in $\mathrm{mol} \mathrm{L}^{-1} \mathrm{~min}^{-1}$ ) of this reaction?

A
$5 x$
B
$x$
Correct answer
C
$\frac{x}{5}$
D
$-\frac{x}{5}$

Solution

Given reaction, $\begin{aligned} & 5 \mathrm{Br}^{-}(\mathrm{aq})+\mathrm{BrO}_3^{-}(\mathrm{aq})+6 \mathrm{H}^{+}(\mathrm{aq}) \rightarrow 3 \mathrm{Br}_2(\mathrm{aq})+3 \mathrm{H}_2 \mathrm{O}(\mathrm{l}) \\ & -\frac{\Delta\left[\mathrm{Br}^{-}\right]}{\Delta \mathrm{t}}=\mathrm{x} \mathrm{~mol} \mathrm{~L} \\ & \text {-1 } \mathrm{min}^{-1} \\ & \text { Rate of Reaction }=-\frac{1}{5} \frac{\mathrm{~d}\left[\mathrm{Br}^{-}\right]}{\mathrm{dt}} \\ & =\frac{1}{5} \mathrm{x} \end{aligned}$

Hence, the correct answer is option: 'C'.

Solution

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