At 298 K, the standard reduction potential for Cu^(2+)/Cu electrode is 0.34 V. Given : K_spCu(OH)_2=1×10^(-20) Take 2.303RT/F=0.059 V The reduction…

Question

At 298 K, the standard reduction potential for Cu^(2+)/Cu electrode is 0.34 V. Given : K_spCu(OH)_2=1×10^(-20) Take 2.303RT/F=0.059 V The reduction potential at pH=14 for the above couple is (-)x×10^(-2) V. The value of x is

MARKS Content Team · Accepted Answer

Correct answer: 25. For the reaction: Cu^(2+)aq+2e^(-)→Cus The reduction potential is E=E^(ο)-RT/2Fln1/(Cu^(2+)) From the given data pH = 14 and K_sp=CuOH_2=1.0×10^(-20), we get H^(+)=10^(-14)M,OH^(-)=K_WH^(+)=(10^(-14)M^2)/(10^(-14)M)=1M Cu^(2+)=K_spOH-^2=(1.0×10^(-20)M^2)/1M=1.0×10^(-20)M E=0.34V-0.059V/2log1/(1.0×10^(-20))=0.34V-(0.059×20V)/2E=0.34-0.59 =-0.25 V

At $298 K$ , the standard reduction potential for ${Cu}^{2 +} / Cu$ electrode is $0.34 V$ . Given : $K_{sp} Cu (OH)_{2} = 1 \times 10^{- 20}$ Take $\frac{2.303 RT}{F} = 0.059 V$ The reduction potential at $pH = 14$ for the above couple is $(-) x \times 10^{- 2} V$ . The value of x is

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Relevant Questions

At 298 K, the standard reduction potential for Cu2+/Cu electrode is 0.34 V. Given : KspCu(OH)2=1×10-20 Take 2.303RTF=0.059 V The reduction potential at pH=14 for the above couple is (-)x×10-2 V. The value of x is

Solution

Relevant Questions

At $298 K$ , the standard reduction potential for ${Cu}^{2 +} / Cu$ electrode is $0.34 V$ . Given : $K_{sp} Cu (OH)_{2} = 1 \times 10^{- 20}$ Take $\frac{2.303 RT}{F} = 0.059 V$ The reduction potential at $pH = 14$ for the above couple is $(-) x \times 10^{- 2} V$ . The value of x is