Assuming very dilute aqueous solution of urea, calculate the vapour pressure of solution (in mm of Hg) of 0.1 moles of urea in 180 grams of water at…

Question

Assuming very dilute aqueous solution of urea, calculate the vapour pressure of solution (in mm of Hg) of 0.1 moles of urea in 180 grams of water at 25^oC is (The vapour pressure of water at 25^oC is 24 mm Hg)

MARKS Content Team · Accepted Answer

Correct answer: (C) 23.76. From Raoult's law for very dilute solution. (p^o-p_s)/(p^o)=w/m×M/W (24-p_s)/24=0.1×18/180 24-p_s=0.24 ∴ p_s=24-0.24=23.76 mm Hg

Assuming very dilute aqueous solution of urea, calculate the vapour pressure of solution (in mm of Hg) of 0.1 moles of urea in $180 grams$ of water at $25^{o} C$ is (The vapour pressure of water at $25^{o} C$ is 24 mm Hg)

Solution

More Solutions Questions

Assuming very dilute aqueous solution of urea, calculate the vapour pressure of solution (in mm of Hg) of 0.1 moles of urea in 180 grams of water at 25oC is (The vapour pressure of water at 25oC is 24 mm Hg)

Solution

More Solutions Questions

Assuming very dilute aqueous solution of urea, calculate the vapour pressure of solution (in mm of Hg) of 0.1 moles of urea in $180 grams$ of water at $25^{o} C$ is (The vapour pressure of water at $25^{o} C$ is 24 mm Hg)