Q112 / 150 · JEE Main 2006 · Physics
Assuming the sun to be a spherical body of radius $\mathrm{R}$ at a temperature of $\mathrm{T} \mathrm{K}$, evaluate the total radiant power, incident on Earth, at a distance $r$ from the Sun.
- A$\frac{\mathrm{R}^2 \sigma \mathrm{T}^4}{\mathrm{r}^2}$
- B$\frac{4 \pi r_0^2 R^2 \sigma T^4}{r^2}$
- Correct answerC$\frac{\pi r_0^2 R^2 \sigma T^4}{r^2}$
- D$\frac{r_0^2 R^2 \sigma T^4}{4 \pi r^2}$
Solution
$\frac{\pi r_0^2}{4 \pi r^2}\left(\sigma \mathrm{T}^4 \cdot 4 \pi \mathrm{R}^2\right)=\frac{\sigma \pi \mathrm{T}^4 \mathrm{R}^2 \mathrm{r}_0^2}{\mathrm{r}^2}$
Hence, the correct answer is option: 'C'.