Q48 / 90 · JEE Main 2012 (Offline) · Mathematics

Assuming the balls to be identical except for difference in colours, the number of ways in which one or more balls can be selected from $10$ white, $9$ green and $7$ black balls is

  • A
    $880$
  • B
    $629$
  • C
    $630$
  • Correct answer
    D
    $879$

Solution

Number of ways of selecting one or more balls from $10$ white, $9$ green, and $7$ black balls $=(10+1)(9+1)(7+1)-1=11 \times 10 \times 8-1=879.$

Hence, the correct answer is option: 'D'.

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