Q122 / 180 · AIIMS 2018 (27 May) · Physics
Assume that each diode shown in the figure has a forward bias resistance of $50 \Omega$ and an infinite reverse bias resistance. The current through the resistance $150 \Omega$ is


- A$0.66 \mathrm{~A}$
- B$0.05 \mathrm{~A}$
- Czero
- Correct answerD$0.04 \mathrm{~A}$
Solution
In the circuit, diode $D_1$ is reverse biased and offers infinite resistance, diode $D_2$ is forward biased and offers $50 \Omega$ resistance. The equivalent circuit is shown in the figure. Total resistance of the circuit,
$R=50 \Omega+50 \Omega+150 \Omega=250 \Omega$
The current in the circuit,
$I=\frac{V}{R}=\frac{10 \mathrm{~V}}{250 \Omega}=0.04 \mathrm{~A}$
So, current through the resistance $150 \Omega$ is $0.04 \mathrm{~A}$.


Hence, the correct answer is option: 'D'.