Q16 / 160 · TS EAMCET 2022 (20 Jul Shift 1) · Chemistry
Assertion : $\left[\mathrm{B}\left(\mathrm{OH}_2\right)_6\right]^{3+}$ and $\left[\mathrm{B}(\mathrm{OH})_4\right]^{-}$form octahedral and tetrahedral structures.
Reason : Being electron deficient, boron readily reacts with Lewis bases like $\mathrm{H}_2 \mathrm{O}, \mathrm{OH}^{-}$
The correct option among the following is
- A(A) is true, (R) is true and (R) is the correct explanation for (A)
- B(A) is true, (R) is true but (R) is not the correct explanation for (A)
- C(A) is true but (R) is false
- Correct answerD(A) is false but (R) is true
Solution
Hexacoordinated $\left[\mathrm{B}\left(\mathrm{OH}_2\right)_6\right]^{3+}$ is not possible as ' $\mathrm{B}$ ' does not have 'd' orbital to accommodate $6 \mathrm{H}_2 \mathrm{O}$ molecules.
Hence, the correct answer is option: 'D'.