Q16 / 160 · TS EAMCET 2022 (20 Jul Shift 1) · Chemistry

Assertion : $\left[\mathrm{B}\left(\mathrm{OH}_2\right)_6\right]^{3+}$ and $\left[\mathrm{B}(\mathrm{OH})_4\right]^{-}$form octahedral and tetrahedral structures. Reason : Being electron deficient, boron readily reacts with Lewis bases like $\mathrm{H}_2 \mathrm{O}, \mathrm{OH}^{-}$ The correct option among the following is

  • A
    (A) is true, (R) is true and (R) is the correct explanation for (A)
  • B
    (A) is true, (R) is true but (R) is not the correct explanation for (A)
  • C
    (A) is true but (R) is false
  • Correct answer
    D
    (A) is false but (R) is true

Solution

Hexacoordinated $\left[\mathrm{B}\left(\mathrm{OH}_2\right)_6\right]^{3+}$ is not possible as ' $\mathrm{B}$ ' does not have 'd' orbital to accommodate $6 \mathrm{H}_2 \mathrm{O}$ molecules.

Hence, the correct answer is option: 'D'.

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