Q96 / 180 · AIIMS 2015 · Physics
Assertion : An emf $\varepsilon$ is induced in a closed loop when magnetic flux is varied. The induced electric field $E$ is not a conservative field.
Reason : The line integral $\oint \vec{E} \cdot \overrightarrow{d l}$ around the closed loop is non-zero.
- Correct answerAIf both assertion and reason are true and reason is the correct explanation of assertion.
- BIfboth assertion and reason are true but reason is not the correct explanation of assertion.
- CIf assertion is true but reason is false.
- DIf both assertion and reason are false.
Solution
We know
$$
\varepsilon=\oint \vec{E} \cdot d \vec{l}=-\frac{d \phi_B}{d t}
$$
As $\oint \vec{E} \cdot d \vec{l} \neq 0$,
the induced electric field is non-conservative in nature.
Hence, the correct answer is option: 'A'.