Q13 / 225 · JEE Main 2004 · Chemistry
As the temperature is raised from $20^{\circ} \mathrm{C}$ to $40^{\circ} \mathrm{C}$, the average kinetic energy of neon atoms changes by a factor of which of the following?
- A$1 / 2$
- B2
- Correct answerC$\frac{313}{293}$
- D$\sqrt{\frac{313}{293}}$
Solution
$\frac{E_1}{E_2}=\frac{T_1}{T_2}$
$\frac{E_1}{E_2}=\frac{293}{313}$
$\because$ factor $=\frac{313}{293}$
Hence, the correct answer is option: 'C'.