\begin{array}{c|c|c} A & B & Y \\\hline 0 & 0 & 1 \\0 & 1 & 1 \\1 & 0 & 0 \\1 & 1 & 1\end{array} To obtain the given truth table, following logic gate should be placed at G:

• A

  OR Gate
• B

  AND Gate
• Correct answer
  C

  NOR Gate
• D

  NAND Gate

Solution

For NOR gate : $\overline{\mathrm{A} \overline{\mathrm{B}}}=\overrightarrow{\mathrm{A}}+\mathrm{B}$

Hence, the correct answer is option: 'C'.