Q117 / 160 · TS EAMCET 2019 (04 May Shift 2) · Mathematics
Area of the region (in square units) bounded by the curve $y=x^2+4$ and the line $y=5 x-2$ is
- A$\frac{1}{2}$
- B$\frac{1}{12}$
- C2
- Correct answerD$\frac{1}{6}$
Solution
We have,
$$
y=x^2+4, y=5 x-2
$$
Solving equation, we get

$(2,8)$ and $(3,13)$ Area of shaded region $$ \begin{aligned} & \int_2^3\left((5 x-2)-\left(x^2+4\right) d x\right. \\ & =\int_2^3\left(5 x-x^2-6\right) d x=\left[\frac{5 x^2}{2}-\frac{x^3}{3}-6 x\right]_2^3 \\ & =\left[\left(\frac{45}{2}-9-18\right)-\left(10-\frac{8}{3}-12\right)\right]=\frac{1}{6} \end{aligned} $$

$(2,8)$ and $(3,13)$ Area of shaded region $$ \begin{aligned} & \int_2^3\left((5 x-2)-\left(x^2+4\right) d x\right. \\ & =\int_2^3\left(5 x-x^2-6\right) d x=\left[\frac{5 x^2}{2}-\frac{x^3}{3}-6 x\right]_2^3 \\ & =\left[\left(\frac{45}{2}-9-18\right)-\left(10-\frac{8}{3}-12\right)\right]=\frac{1}{6} \end{aligned} $$
Hence, the correct answer is option: 'D'.