Q79 / 225 · JEE Main 2005 · Mathematics

Area of the greatest rectangle that can be inscribed in the ellipse $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ is

  • Correct answer
    A
    $2 a b$
  • B
    $a b$
  • C
    $3a b$
  • D
    $\frac{a}{b}$

Solution

Figure
Area of rectangle $A B C D=(2 a\cos \theta)$ $(2 b \sin \theta)=2 a b \sin 2 \theta$ $\Rightarrow$ Area of greatest rectangle is equal to $2 a b$ when $\sin 2 \theta=1$.

Hence, the correct answer is option: 'A'.

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