Q44 / 160 · WBJEE 2010 · Mathematics

$\mathrm{A}=\{1,2,3,4\}, \mathrm{B}=\{1,2,3,4,5,6\}$ are two sets, and function $\mathrm{f}: \mathrm{A} \rightarrow \mathrm{B}$ is defined by $\mathrm{f}(\mathrm{x})=\mathrm{x}+2 \forall \mathrm{x} \in \mathrm{A}$, then the function $\mathrm{f}$ is

  • A
    bijective
  • B
    onto
  • Correct answer
    C
    one-one
  • D
    many-one

Solution

Hints: $\mathrm{f}(\mathrm{x})=\mathrm{f}(\mathrm{y}) \Rightarrow \mathrm{x}+2=\mathrm{y}+2 \Rightarrow \mathrm{x}=\mathrm{y} \quad \therefore$ one-one

Hence, the correct answer is option: 'C'.

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