An unsaturated hydrocarbon $\mathrm{X}$ on ozonolysis gives $\mathrm{A}$. Compound $\mathrm{A}$ when warmed with ammoniacal silver nitrate forms a bright silver mirror along the sides of the test tube. The unsaturated hydrocarbon $\mathrm{X}$ is :

As $\left(\mathrm{A}\right)$ compound given positive Tollen's test hence it may consist  $-\mathrm{CHO}$ (aldehyde group) or it can be $\mathrm{HCOOH}$

So for the given option :

(3) ${\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{C}\equiv \mathrm{CH}\stackrel{\mathrm{Ozonolysis}}{⟶}{\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{COOH}+\underset{\underset{+\mathrm{ve} \mathrm{tollen}\text{'}\mathrm{s} \mathrm{test}}{\left(\mathrm{A}\right)}}{\mathrm{HCOOH}}$

and for other compounds (options):

(3) ${\mathrm{CH}}_3-\mathrm{C}\equiv \mathrm{C}-{\mathrm{CH}}_3\stackrel{\mathrm{Ozonolysis}}{⟶}\underset{(\mathrm{Does} \mathrm{not} \mathrm{show} \mathrm{tollen}\text{'}\mathrm{s} \mathrm{test})}{2{\mathrm{CH}}_3-\mathrm{COOH}}$