Q76 / 160 · AP EAMCET 2022 (06 Jul Shift 2) · Mathematics

An unbiased dice with faces marked 1, 2,3, 4,5 , and 6 is rolled four times. Out of four face values obtained, the probability that the minimum face value is not less than 2 and the maximum face value is not greater than 5 is

  • Correct answer
    A
    $16 / 81$
  • B
    $1 / 81$
  • C
    $80 / 81$
  • D
    $65 / 81$

Solution

Here, the face value should be 2, 3, 4, 5 . $P$ (getting a number not less than 2 and not more than 5 in a single throw) $=\frac{4}{6}=\frac{2}{3}$ $\therefore$ Required probability $=\left(\frac{2}{3}\right)^4=\frac{16}{81}$

Hence, the correct answer is option: 'A'.

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