Q12 / 90 · KVPY 2015 (SB/SX) · Chemistry
An organic compound having molecular formula $\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}$ under goes oxidation with $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} / \mathrm{H}_{2} \mathrm{SO}_{4}$ to produce $\mathrm{X}$ which contains $40 \%$ carbon, $6.7 \%$ hydrogen and $53.3 \%$ oxygen. The molecular formula of the compound $\mathrm{X}$ is
- A$\mathrm{CH}_{2} \mathrm{O}$
- Correct answerB$\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{O}_{2}$
- C$\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{O}$
- D$\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}_{2}$
Solution
$\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}-\mathrm{K}_{2} \mathrm{C}_{2} \mathrm{O}_{7} / \mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{CH}_{3} \mathrm{COOH}$
$\% \mathrm{C}=\frac{24}{60} \times 100=40 \%, \% \mathrm{H}=\frac{4}{60} \times 100=6.7 \%, \% \mathrm{O}=\frac{32}{60} \times 100=53.3 \%$
Hence, the correct answer is option: 'B'.