Q73 / 90 · JEE Main 2014 (06 Apr) · Physics

An open glass tube is immersed in mercury in such a way that a length of 8 cm extends above the mercury level. The open end of the tube is then closed and sealed and the tube is raised vertically up by additional 46 cm. What will be length of the air column above mercury in the tube now ?
(Atmospheric pressure = 76 cm of Hg)

  • Correct answer
    A
    16 cm
  • B
    22 cm
  • C
    38 cm
  • D
    6 cm

Solution

Using isothermal process conditions

Figure

⇒ P 1 V 1 = P 2 V 2 ⇒ P 1 A ℓ 1 = P 2 A ℓ 2

8 p 0 = xp ⇒ p = 8 p 0 x     (here p0 = 76 cm of Hg)

8 p 0 x + ρ m g 54 - x = ρ m g (76)

8 x + 54 - x 76 = 1

x = 16 cm

Hence, the correct answer is option: 'A'.

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