An object moves at a constant speed along a circular path in a horizontal plane with centre at the origin. When the object is at $x=+2 \mathrm{m}$, its velocity is $-4\hat{\mathrm{j}} \mathrm{m} {\mathrm{s}}^{-1}$ . The object’s velocity $\left(v\right)$ and acceleration $\left(a\right)$ at $x=–2 \mathrm{m}$ will be

• A

  $v=4\hat{\mathrm{i}} \mathrm{m} {\mathrm{s}}^{-1}, a=8\hat{\mathrm{j}} \mathrm{m} {\mathrm{s}}^{-2}$
• Correct answer
  B

  $v=4\hat{\mathrm{j}} \mathrm{m} {\mathrm{s}}^{-1}, a=8\hat{\mathrm{i}} \mathrm{m} {\mathrm{s}}^{-2}$
• C

  $v=-4\hat{\mathrm{j}} \mathrm{m} {\mathrm{s}}^{-1}, a=8\hat{\mathrm{i}} \mathrm{m} {\mathrm{s}}^{-2}$
• D

  $\mathrm{v}=-4\hat{\mathrm{i}} \mathrm{m} {\mathrm{s}}^{-1}, \mathrm{a}=-8\hat{\mathrm{j}} \mathrm{m} {\mathrm{s}}^{-2}$

Hence, the correct answer is option: 'B'.