Q142 / 160 · AP EAMCET 2024 (20 May Shift 1) · Physics
An object lying 100 cm inside water is viewed normally from air. If the refractive index of water is $\frac{4}{3}$, then the apparent depth of the object is
- A100 cm
- B50 cm
- C25 cm
- Correct answerD75 cm
Solution
Real depth $=100 \mathrm{~cm}, \mu=\frac{4}{3}$
$\therefore \quad$ Apparent depth $=\frac{\text { Real depth }}{\mu}=\frac{100 \times 3}{4}=75 \mathrm{~cm}$
Hence, the correct answer is option: 'D'.