Q83 / 90 · JEE Main 2024 (27 Jan Shift 2) · Physics

An object is placed in a medium of refractive index 3. An electromagnetic wave of intensity 6×108 W m-2 falls normally on the object and it is absorbed completely. The radiation pressure on the object would be (speed of light in free space =3×108 m s-1 ):

  • A
    36 N m-2
  • B
    18 N m-2
  • Correct answer
    C
    6 N m-2
  • D
    2 N m-2

Solution

The formula to calculate the radiation pressure is given by

P=Iv   ...1

Also, the velocity of the electromagnetic wave can be expressed as

μ=cv   ...2

Equations (1) and (2) imply that

P=I·μc=6×108×33×108=6 N m-2

Hence, the correct answer is option: 'C'.

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