An $L.C.R.$ circuit contains resistance of $110 \mathrm{\Omega }$ and a supply of $220 \mathrm{V}$ at $300 \mathrm{rad} {\mathrm{s}}^{-1}$ angular frequency. If only capacitance is removed from the circuit, current lags behind the voltage by $45°$. If on the other hand, the only the inductor is removed the current leads by $45°$ with the applied voltage. The $R.M.S.$ current flowing in the circuit will be:

• A

  $2.5 \mathrm{A}$
• Correct answer
  B

  $2 \mathrm{A}$
• C

  $1 \mathrm{A}$
• D

  $1.5 \mathrm{A}$

Hence, the correct answer is option: 'B'.