Q127 / 200 · NEET 2021 · Physics

An inductor of inductance L, a capacitor of capacitance C and a resistor of resistance R are connected in series to an ac source of potential difference V volt as shown in figure.Potential difference across L,C and R is 40 V,10 V and 40 V, respectively. The amplitude of current flowing through L-C-R series circuit is 102 A. The impedance of the circuit is :

Figure

  • A
    42Ω
  • B
    5/2Ω
  • Correct answer
    C
    5Ω
  • D
    4Ω

Solution

Figure

V=VR2+VC-VL2

=402+(10-40)2

=50 volt

irms=VrmsZ

⇒  Z=vrmsirms

⇒  Z=Vrms×210

⇒Z=2×50102

⇒Z=5 Ω

Hence, the correct answer is option: 'C'.

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