An equilateral triangle is inscribed in the ellipse whose equation is x^2+4y^2=4. One vertex of the triangle is 0,1 and one altitude is contained in…

Question

An equilateral triangle is inscribed in the ellipse whose equation is x^2+4y^2=4. One vertex of the triangle is 0,1 and one altitude is contained in the y-axis. If the length of each side is k√3 units, then k is

MARKS Content Team · Accepted Answer

Correct answer: (A) 16/13. (x^2)/4+(y^2)/1=1 Equation of AB is y=√3x+1 x^2+43x^2+2√3x+1=4 ⇒13x^2+8√3x=0⇒x=(-8√3)/13 BC=(16√3)/13 units

An equilateral triangle is inscribed in the ellipse whose equation is $x^{2} + 4 y^{2} = 4 .$ One vertex of the triangle is $(0,1)$ and one altitude is contained in the $y$ -axis. If the length of each side is $k \sqrt{3}$ units, then $k$ is

Solution

More Ellipse Questions

An equilateral triangle is inscribed in the ellipse whose equation is x2+4y2=4. One vertex of the triangle is 0,1 and one altitude is contained in the y-axis. If the length of each side is k3 units, then k is

Solution

More Ellipse Questions

An equilateral triangle is inscribed in the ellipse whose equation is $x^{2} + 4 y^{2} = 4 .$ One vertex of the triangle is $(0,1)$ and one altitude is contained in the $y$ -axis. If the length of each side is $k \sqrt{3}$ units, then $k$ is