Q36 / 164 · NTA Abhyas (NEET) 2020 · Chemistry · Solid State

An element (atomic mass = 100 g/mol) having bcc structure has unit cell edge 400 pm. Then density of the element is

A
$10.376 g / c m^{3}$
Correct answer
B
$5.188 g / c m^{3}$
C
$7.289 g / c m^{3}$
D
$2.144 g / c m^{3}$

Solution

In bcc structure number of atoms (Z = 2)
Density

= \frac{Z \times M}{a^{3} \times N_{A}}

= \frac{2 \times 100}{(400 \times 1 0^{- 10})^{3} \times 6.02 \times 1 0^{23}}

= 5.188 g / c m^{3}

Hence, the correct answer is option: 'B'.

More Solid State Questions

The coordination number of the B a 2 + ions is barium fluoride is 8. The coordination number of the fluoride ion is
In chromium chloride C r C l 3 , C l - ions have cubic close packed arrangement and C r 3 + ions are present in the octahedral holes. The fr
A solid A B has rocksalt structure. If the edge length is 400 p m and the radius of the cation is 80 p m , then the radius of the anion is
Which of the following arrangements correctly represents hexagonal and cubic close packed structure respectively?
A compound AB has a rock type structure with A : B = 1 : 1. The formula weight of AB is 6.023 y amu and the closest A – B distance is y 1 /
If ′ a ′ stands for the edge length of the cubic systems: simple cubic, body centred cubic and face centred cubic, then the ratio of radii o