Q67 / 90 · JEE Main 2021 (25 Feb Shift 2) · Physics

An electron of mass $m_{e}$ and a proton of mass $m_{p} = 1836 m_{e}$ are moving with the same speed. The ratio of their de Broglie wavelength $\frac{λ_{e l e c t r o n}}{λ_{p r o t o n}}$ will be :

Correct answer
A
$1836$
B
$\frac{1}{1836}$
C
$918$
D
$1$

Solution

Given mass of electron

= m_{e}

Mass of proton

= m_{p}

∴

given

m_{p} = 1836 m_{e}

From de-Broglie wavelength

λ = \frac{h}{p} = \frac{h}{mv}

\frac{λ_{e}}{λ_{p}} = \frac{m_{p}}{m_{e}}

= \frac{1836 m_{e}}{m_{e}}

\frac{λ_{e}}{λ_{p}} = 1836

Hence, the correct answer is option: 'A'.

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