Q63 / 90 · JEE Main 2017 (02 Apr) · Physics

An electron beam is accelerated by a potential difference V to hit a metallic target to produce X-rays. It produces continuous as well as characteristic X-rays. If λmin is the smallest possible wavelength of X-ray in the spectrum, the variation of logλmin with logV is correctly represented in :

  • A

    Figure

  • Correct answer
    B

    Figure

  • C

    Figure

  • D

    Figure

Solution

K.E.=eV,

KE=The kinetic energy of electron

The maximum energy of photon=K.E.

eV=hCλmin

⇒λmin V=hCe=constant

Taken log in both sides

lnλmin+lnV=lnconstant

⇒lnλmin=-lnV+ln(constant)

y=-ax+c the straight line of negative slope.

Hence, the correct answer is option: 'B'.

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