Q147 / 270 · NDA 2023 (Phase 1) · General Ability
An electric bulb is rated as 220 V and 80 W . When it is operated on 110 V , the power rating would be :
- A80 W
- B60 W
- Correct answerC40 W
- D20 W
Solution
As, $\mathrm{P}=\mathrm{IV}$
Here, $\mathrm{v}_1=220 \mathrm{v}, \mathrm{p}_1=80 \mathrm{~W}$ and $\mathrm{v}_2=110 \mathrm{v}$
$\frac{p_2}{p_1}=\frac{v_2}{v_1}$
$\mathrm{p}_2=\frac{\mathrm{p}_1 \mathrm{v}_2}{\mathrm{v}_1}$
$=\frac{80 \times 110}{220}$
$\mathrm{p}_2=40 \mathrm{~W}$
Hence, the correct answer is option: 'C'.