An atom absorbs a photon of wavelength $500 \mathrm{nm}$ and emits another photon of wavelength $600 \mathrm{nm}$. The net energy absorbed by the atom in this process is $n\times {10}^{-4}\mathrm{eV}$. The value of$n$is [Assume the atom to be stationary during the absorption and emission process] (Take $h=6.6\times {10}^{-34}\mathrm{J} \mathrm{s}$ $$ and $c=3\times {10}^8 \mathrm{m} {\mathrm{s}}^{-1}$ ).

Hence, the correct answer is 4125.