Q118 / 180 · NEET 2017 · Physics

An arrangement of three parallel straight wires placed perpendicular to plane of paper carrying same current I along the same direction is shown in Figure. Magnitude of force per unit length on the middle wire B is given by

Figure

  • A
    μ0I22πd
  • B
    2μ0I2πd
  • C
    2μ0I2πd
  • Correct answer
    D
    μ0I22πd

Solution

Force per unit length between two parallel long current carrying wires is = μ 0 I 1 I 2 2πd
Here, force between BC and AB will be same in magnitude.

Figure

FBC=FBA=μ0I22πd

  Fres=FBC2+FBA2

⟹Fres=2μ0I22πd=μ0I22πd

Hence, the correct answer is option: 'D'.

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