Q12 / 90 · JEE Main 2018 (08 Apr) · Chemistry

An aqueous solution contains an unknown concentration of Ba2+. When 50 mL of a 1 M solution of Na2SO4 is added, BaSO4 just begins to precipitate. The final volume is 500 mL. The solubility product of BaSO4 is 1×10-10. What is the original concentration of Ba2+?

  • A
    1.0×10-10M
  • B
    5×10-9M
  • C
    2×10-9M
  • Correct answer
    D
    1.1×10-9M

Solution

Ba+2+SO42−⇌BaSO4(s)ppt

Final conc. of [SO42−]=MV1V1+V2=1×50500=0.1M

Final conc.of [Ba+2] When BaSO4 start precipitating

KSP=QSP=[Ba+2][SO42−]

10−10=[Ba+2](0.1M)

Initial conc. [Ba+2]; initial volume was =500-50=450 ml
M1V1=M2V2

M1=M2V2V1=10−9×500450

M1=1.1×10−9M
 

Hence, the correct answer is option: 'D'.

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