Q2 / 60 · KVPY 2011 (SA) · Chemistry
An aqueous buffer is prepared by adding $100 \mathrm{ml}$ of $0.1 \mathrm{~mol} \mathrm{t}^{-1}$ acetic acid to $50 \mathrm{ml}$ of $0.2 \mathrm{~mol} \mathrm{I}^{-1}$ of sodium acetate. If $\mathrm{pKa}$ of acetic acid is $4.76$, the $\mathrm{pH}$ of the buffer is
- A$4.26$
- B$5.76$
- C$3.76$
- Correct answerD$4.76$
Solution
Meq of $\mathrm{CH}_{3} \mathrm{COOH}=100 \times 0.1 \times 1=10$
Meq of $\mathrm{CH}_{3} \mathrm{COONa}=50 \times 0.2 \times 1=10$
$\begin{array}{l}
\mathrm{pH}=\mathrm{pK}_{\mathrm{a}}+\log \frac{\left[\mathrm{CH}_{3} \mathrm{COO}^{-}\right]}{\left[\mathrm{CH}_{3} \mathrm{COOH}\right]} \\
\mathrm{pH}=4.76+\log \frac{10}{10} \\
\mathrm{pH}=4.76+\log 1 \\
\mathrm{pH}=4.76
\end{array}$
Hence, the correct answer is option: 'D'.