An alternating voltage $V\left(t\right)=220\sin \left(100\pi t\right)$ volt is applied to a purely resistive load of $50 \mathrm{\Omega }$ . The time taken for the current to rise from half of the peak value to the peak value is:

• A

  $7.21 \mathrm{m}\mathrm{s}$
• B

  $5.25 \mathrm{m}\mathrm{s}$
• C

  $2.24 \mathrm{m}\mathrm{s}$
• Correct answer
  D

  $3.33 \mathrm{m}\mathrm{s}$

Hence, the correct answer is option: 'D'.