Q31 / 44 · NTA Abhyas (JEE Main) 2020 · Physics · Alternating Current

An alternating current is given by i=i1 cos ωt+i2 sin ωt. The value of rms current is 

  • A
    i1+i22
  • B
    i1+i22
  • Correct answer
    C
    i12+i222
  • D
    i12+i222

Solution

i=i1cos ωt+i2sin ωt

i2mean=i12 cos2ωt¯+i22 sin2ωt¯+i1i2 cos ωt sin ωt¯

i12×12×i22×12+2i1i2×0

irms=i2mean=i12+i222

Hence, the correct answer is option: 'C'.

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