Q6 / 110 · VITEEE 2024 · Chemistry
Among the following, the molecules /ions having same bond order are
- ACO and $\mathrm{O}_2^{2-}$
- B$\mathrm{O}_2^{-}$and CO
- Correct answerC$\mathrm{O}_2^{2-}$ and $\mathrm{B}_2$
- DCO and $\mathrm{N}_2^{+}$
Solution
$\begin{aligned} & \mathrm{O}_2^{2-}\left(18 e^{-}\right): K K \sigma(2 s)^2 \sigma^*(2 s)^2 \sigma\left(2 p_z\right)^2 \pi \\ & \quad\left(2 p_x\right)^2 \pi^*\left(2 p_y\right)^2 \pi^*\left(2 p_x\right)^2 \pi^*\left(2 p_y\right)^2\end{aligned}$
$\begin{gathered}\text { Bond order }(\mathrm{B} . \mathrm{O})=\frac{8-6}{2}=1 \\ \mathrm{~B}_2\left(10 e^{-}\right): K K \sigma(2 s)^2 \sigma^*(2 s)^2 \pi\left(2 p_x\right)^1 \pi\left(2 p_y\right)^1 \\ \text { B.O }=\frac{4-2}{2}=1\end{gathered}$
Therefore, $\mathrm{O}_2^{2-}$ and $\mathrm{B}_2$ have identical bond order.
Hence, the correct answer is option: 'C'.