Q14 / 160 · AP EAMCET 2023 (15 May Shift 2) · Chemistry

Among the following, the correctly matched pair is

  • A
    electron deficient hydride $-\mathrm{SiH}_4$
  • B
    saline hydride - $\mathrm{CrH}$
  • C
    electron precise hydride - HF
  • Correct answer
    D
    electron rich hydride $-\mathrm{NH}_3$

Solution

$\mathrm{NH}_3$ is an electron-rich hydride as $\mathrm{N}$-atom belongs to group - 15 and uses three of its valence electrons to make three $\mathrm{N}-\mathrm{H}$ bonds and the remaining two electrons form a lone pair.

Hence, the correct answer is option: 'D'.

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