Q31 / 160 · TS EAMCET 2020 (10 Sep Shift 2) · Chemistry

Among the following series of transition metal ions, the one in which all the metal ions have $3 d^2, 3 p^6$ electronic configuration is (Atomic number, $\mathrm{Ti}=22, \mathrm{~V}=23, \mathrm{Cr}=24$, $\mathrm{Mn}=25$ )

  • A
    $\mathrm{Ti}^{3+}, \mathrm{V}^{2+}, \mathrm{Cr}^{3+}$ and $\mathrm{Mn}^{4+}$
  • B
    $\mathrm{Ti}^{+}, \mathrm{V}^{4+}, \mathrm{Cr}^{6+}$ and $\mathrm{Mn}^{7+}$
  • C
    $\mathrm{Ti}^{4+}, \mathrm{V}^{3+}, \mathrm{Cr}^{2+}$ and $\mathrm{Mn}^{3+}$
  • Correct answer
    D
    $\mathrm{Ti}^{2+}, \mathrm{V}^{3+}, \mathrm{Cr}^{4+}$ and $\mathrm{Mn}^{5+}$

Solution

(d) Among the given series of transition metal ions, one in which all metal ions have $3 d^2, 3 p^6$ electronic configuration is : Option (d), i.e. $\mathrm{Ti}(Z=22) \rightarrow \mathrm{Ti}^{2+}$ (has 20 electrons) $\mathrm{V}(Z=23) \rightarrow \mathrm{V}^{3+}$ (has 20 electrons) $\mathrm{Cr}(Z=24) \rightarrow \mathrm{Cr}^{4+}$ (has 20 electrons) and $\mathrm{Mn}(Z=25) \rightarrow \mathrm{Mn}^{5+}$ (has 20 electrons) Thus, all can show $3 d^2 3 p^6$ electronic configuration

Hence, the correct answer is option: 'D'.

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